Metre Stick:

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$I = \displaystyle\frac{1}{3} ml^2$

**Figure 11:** The Meter Stick
$\begin{figure} \begin{center} \leavevmode \epsfxsize=4 cm \epsfbox{figs/sho4.eps} \end{center}\end{figure}$

$\begin{displaymath}\frac{1}{3}ml^2\frac{d^2\theta }{dt^2} = -mg\frac{l}{2}\sin\theta \end{displaymath}$

(23)

$\begin{displaymath}\rightarrow\frac{d^2\theta }{dt^2}\sim -\frac{3}{2} g/l\ \theta \end{displaymath}$

(24)

gabor@theory.uwinnipeg.ca
2001-01-05