Simple Pendulum:

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I = mL²

**Figure 10:** Simple Pendulum
$\begin{figure} \begin{center} \leavevmode \epsfxsize=4 cm \epsfbox{figs/sho3.eps} \end{center}\end{figure}$

$\begin{displaymath}\frac{d^2\theta }{dt^2} = -\frac{g}{L}\theta\qquad T = 2\pi\sqrt{\frac{L}{g}} \end{displaymath}$

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gabor@theory.uwinnipeg.ca
2001-01-05