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Relation Between Torque and Angular Acceleration

Consider a mass m moving in a circle of radius r , acted on by a tangential force Ft as shown in Figure 8.2.

  
Figure 8.2: Torque and angular acceleration
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Using Newton's second law to relate Ft to the tangential acceleration at = r$\alpha$ , where $\alpha$ is the angular acceleration:

Ft = mat = mr$\displaystyle\alpha$

and the fact that the torque about the center of rotation due to Ft is: $\tau$ = Ftr , we get:

$\displaystyle\tau$ = mr 2$\displaystyle\alpha$.

For a rotating rigid body made up of a collection of masses m1,m2.... the total torque about the axis of rotation is:
 
$\displaystyle\tau_{{\:\rm total}}^{}$ = $\displaystyle\sum$$\displaystyle\tau_{i}^{}$   
  = ($\displaystyle\sum$miri2)$\displaystyle\alpha$. (9)
The second line above uses the fact that the angular acceleration of all points in a rigid body is the same, so that it can be taken outside the summation.

Definition: Moment of Inertia of a rigid body

The moment of inertia, I , of a rigid body gives a measure of the amount of resistance a body has to changing its state of rotational motion. Mathematically,

I = $\displaystyle\sum$miri2. (10)

Note: The units of moment of inertia are kg $\cdot$ m 2.

This allows us to rewrite Equation 8.9 as:

 
$\displaystyle\tau_{{\:\rm total}}^{}$ = I$\displaystyle\alpha$ (11)

which is the rotational analogue of Newton's second law.

Note:


next up previous index
Next: Rotational Kinetic Energy Up: Rotational Equilibrium and Dynamics Previous: Center of Gravity

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10/9/1997