When you call a function as &foo, you allow that function access to your current @_ values, and you bypass prototypes. The function doesn't get an empty @_--it gets yours! While not strictly speaking a bug (it's documented that way in perlsub), it would be hard to consider this a feature in most cases.
When you call your function as &foo(), then you do get a new @_, but prototyping is still circumvented.
Normally, you want to call a function using foo(). You may only omit the parentheses if the function is already known to the compiler because it already saw the definition (use but not require), or via a forward reference or use subs declaration. Even in this case, you get a clean @_ without any of the old values leaking through where they don't belong.